Question

(x-3)(x+3)-4x=(x-1)^2

Answer 1

$(x-3)(x+3)-4x=(x-1)^2\\\\x^2-9-4x=x^2-2x+1\\\\-9-1=4x-2x\\\\-10=2x\\\\2x=-10\\\\x=-5$

Answer 2

х²-9-4х=х²-2х+1

х²-х²-4х+2х-9-1=0

-2х-10=0

-2х=10

х=-5

Answer 3

Let's solve the given equation step-by-step:

1. Expand the left-hand side (LHS): (x - 3)(x + 3) - 4x = x^2 + 3x - 3x - 9 - 4x = x^2 - 10x - 9

2. Simplify the right-hand side (RHS): (x - 1)^2 = (x - 1)(x - 1) = x^2 - x - x + 1 = x^2 - 2x + 1

Now, the equation becomes: x^2 - 10x - 9 = x^2 - 2x + 1

3. To solve the equation, we can move all terms to one side: x^2 - x^2 - 10x + 2x - 9 - 1 = 0

4. Simplify: -8x - 10 = 0

5. To isolate x, move the constant term to the other side: -8x = 10

6. Finally, solve for x by dividing both sides by -8: x = 10 / (-8) x = -5/4

So the solution to the equation is x = -5/4.