Question

(49х^-5у-1):(0,7х^3у^-4)

Answer 1

Ответ:

70x²y³

Объяснение:

(49x^5 *y^(-1)):(0,7x^3 *y^(-4))=490/7 *x^(5-3)*y^(-1+4)=70x²y³

Answer 2

To simplify the expression (49x^(-5)y^(-1))/(0.7x^3y^(-4)), you can apply the rules of exponents and perform the division.

Let's break down the steps:

Step 1: Simplify the numerator and denominator separately.

In the numerator, we have 49x^(-5)y^(-1). In the denominator, we have 0.7x^3y^(-4).

Step 2: Simplify the terms with the same base.

For the numerator, we can rewrite 49 as 7^2.

7^2x^(-5)y^(-1) / (0.7x^3y^(-4))

Step 3: Combine the powers with the same base.

In the numerator, add the exponents of x and y.

7^2x^(-5-3)y^(-1-(-4)) / (0.7)

Simplifying further:

7^2x^(-8)y^3 / (0.7)

Step 4: Evaluate the values.

7^2 = 49

x^(-8) can be rewritten as 1/x^8.

y^3 remains the same.

(49 * 1/x^8 * y^3) / (0.7)

Step 5: Divide the coefficients and simplify.

(49 / 0.7) * (1/x^8 * y^3)

Simplifying further:

70 * (1/x^8 * y^3)

Final Result:

The simplified expression is 70 * (1/x^8 * y^3), where x ≠ 0 and y ≠ 0.