Question

√0,16+√(-9)²+√2

Answer 1

$\sqrt{0,16}+\sqrt{(-9)^2}+\sqrt{2\frac{1}{4}}=\sqrt{(0,4)^2}+|-9|+\sqrt{\frac{9}{4}}=0,4+9+\frac{3}{2}=\\\\=\frac{2}{5}+9+\frac{3}{2}=\frac{4+90+15}{10}=\frac{109}{10}=10,9\\\\\\P.S.\; \; \sqrt{a^2}=|a|\; \; \Rightarrow \; \; \; \sqrt{(-9)^2}=|-9|=9\\\\ili:\; \; \; \sqrt{(-9)^2}=\sqrt{+81}=9$

Answer 2

Let's break down the given expression step by step:

1. √0.16: The square root of 0.16 is 0.4 since 0.4 * 0.4 = 0.16.

2. √(-9)²: (-9)² means (-9) * (-9), which equals 81. Therefore, √(-9)² is the square root of 81, which is 9.

3. √2: The square root of 2 is an irrational number, approximately equal to 1.41421356.

Now, let's substitute these values back into the original expression:

√0.16 + √(-9)² + √2 = 0.4 + 9 + 1.41421356 ≈ 10.41421356

So, the approximate value of the given expression is 10.41421356.