Question

Х5 у7= 32,x7y5= 128;​

Answer 1

Ответ:

решение представлено на фото

Answer 2

To solve the equations, let's break them down:

1. Equation 1: x5 * y7 = 32

2. Equation 2: x7 * y5 = 128

To find the values of x and y, we can solve these equations simultaneously.

One approach is to divide Equation 2 by Equation 1:

(x7 * y5) / (x5 * y7) = 128 / 32

Simplifying this expression:

(x7 / x5) * (y5 / y7) = 4

Since the variables x and y appear in different terms on each side of the equation, we can separate them:

(x7 / x5) * (y5 / y7) = (x7 / y7) * (y5 / x5) = 4

Now we have two ratios equal to 4. We can write two separate equations:

(x7 / y7) = 4 / (y5 / x5) ...(Equation A)

(y5 / x5) = 4 / (x7 / y7) ...(Equation B)

Let's substitute some values to make the equations clearer. Suppose x5 = 2 and y7 = 4:

From Equation A:

(x7 / 4) = 4 / (y5 / 2)

Cross-multiplying:

(x7 * y5) = 4 * 4

xy = 16

From Equation B:

(y5 / 2) = 4 / (x7 / 4)

Cross-multiplying:

(y5 * x7) = 4 * 8

xy = 32

Comparing the two results, we find that xy = 16 and xy = 32, which is a contradiction. Therefore, there are no consistent values of x and y that simultaneously satisfy both equations x5 * y7 = 32 and x7 * y5 = 128.