Question

1) √x=5 2) √x-1=3 3) √3x+2=6 4) √7x-8=12

Answer 1

Объяснение:

1.√х=5

х=25

2. √х-1=3

√х=3+1

√х=4

х=16

3.√3х+2=6

√3х=6-2

√3х=4

3х=16

х=16/3

4.√7х-8=12

√7х=12+8

√7х=20

7х=400

х=400/7

Answer 2

Let's solve each of these equations step by step:

1. √x = 5

To isolate x, we square both sides of the equation:

(√x)² = 5² x = 25

So the solution to the equation is x = 25.

2. √x - 1 = 3

To isolate √x, we add 1 to both sides of the equation:

√x = 3 + 1 √x = 4

Now, we square both sides to eliminate the square root:

(√x)² = 4² x = 16

The solution to the equation is x = 16.

3. √(3x + 2) = 6

To isolate √(3x + 2), we square both sides of the equation:

(√(3x + 2))² = 6² 3x + 2 = 36

Next, we subtract 2 from both sides:

3x = 36 - 2 3x = 34

Finally, divide both sides by 3 to solve for x:

x = 34/3

So the solution to the equation is x = 34/3.

4. √(7x - 8) = 12

To isolate √(7x - 8), we square both sides of the equation:

(√(7x - 8))² = 12² 7x - 8 = 144

Next, we add 8 to both sides:

7x = 144 + 8 7x = 152

Finally, divide both sides by 7 to solve for x:

x = 152/7

So the solution to the equation is x = 152/7.