Question

1/3b-1-27b^3-3b/9b^2+1*(3b/9b^2-6b+1 -1/9b^2-1) b≠1/3

Answer 1

Ответ:

Там (3в/9в) и –(3в/9в) сокращаются

Answer 2

To simplify the given expression, let's break it down step by step:

1. Combine like terms in the numerator and denominator separately.
2. Factor out common terms.
3. Cancel out common factors.

Given expression: (1/3b - 1 - 27b^3 - 3b) / (9b^2 + 1) * (3b / 9b^2 - 6b + 1 - 1 / 9b^2 - 1)

Step 1: Combine like terms Numerator: (1/3b - 3b - 1 - 27b^3) Denominator: (9b^2 + 1)

Step 2: Factor out common terms Numerator: (b * (1/3 - 3) - 1 - 27b^3) = (-8b - 1 - 27b^3) Denominator: (9b^2 + 1)

Step 3: The expression does not have any common factors in the numerator and denominator that can be canceled out.

The simplified expression is: (-8b - 1 - 27b^3) / (9b^2 + 1) * (3b / 9b^2 - 6b + 1 - 1 / 9b^2 - 1)

Please note that this expression might still be further simplified, but it cannot be simplified any further without additional information or conditions. If you have any specific conditions or restrictions on the variable "b," please provide them, and I can help you simplify the expression further if possible.