Question

X14/7-X/3=2 X(3X-1.8)*(6X+7)=0

Answer 1

Объяснение:

1 фото это на первое.

2 фото на второе.

Answer 2

To solve the equation X^14/7 - X/3 = 2, we can follow these steps:

Step 1: Get rid of the denominators by multiplying every term by the least common multiple (LCM) of the denominators, which in this case is 21.

21 * (X^14/7) - 21 * (X/3) = 21 * 2

3X^2 - 7X = 42

Step 2: Rearrange the equation to bring all terms to one side and set it equal to zero.

3X^2 - 7X - 42 = 0

Step 3: Factorize the quadratic equation or solve it using the quadratic formula.

To factorize, we need to find two numbers whose product is -42 and whose sum is -7.

The factors of -42 are: -1, 1, -2, 2, -3, 3, -6, 6, -7, 7, -14, 14, -21, 21, 42, -42

By trial and error, we find that -14 and 3 satisfy the conditions. So, we can factorize the equation as follows:

(3X + 6)(X - 7) = 0

Step 4: Set each factor equal to zero and solve for X.

3X + 6 = 0 or X - 7 = 0

3X = -6 or X = 7

X = -2 or X = 7

To solve the equation X(3X - 1.8)(6X + 7) = 0, we set each factor equal to zero and solve for X:

X = 0 or 3X - 1.8 = 0 or 6X + 7 = 0

X = 0 or 3X = 1.8 or 6X = -7

X = 0 or X = 0.6 or X = -7/6

Therefore, the solutions to the equations are:

X = -2, 0, 0.6, 7, -7/6.