Question

X^2-7=-2 x^2-7+2=0 x1+x2=7 x1*x2=2 x3= x4=

Answer 1

$x^{2}-7=-2\\\\x^{2}=-2+7\\\\x^{2}=5\\\\x_{1}=-\sqrt{5}\\\\x_{2}=\sqrt{5}\\\\Otvet:\boxed{-\sqrt{5} ;\sqrt{5}}$

Answer 2

To solve the quadratic equation $x^2 - 7x - 2 = 0$, we can use the quadratic formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Here, $a = 1$, $b = -7$, and $c = -2$. Plugging these values into the formula, we have:

$x = \frac{-(-7) \pm \sqrt{(-7)^2 - 4(1)(-2)}}{2(1)}$

Simplifying further:

$x = \frac{7 \pm \sqrt{49 + 8}}{2}$

$x = \frac{7 \pm \sqrt{57}}{2}$

So, the two solutions are:

$x_1 = \frac{7 + \sqrt{57}}{2}$

$x_2 = \frac{7 - \sqrt{57}}{2}$

As for $x_3$ and $x_4$, you haven't provided any information or equations related to them. If you have additional equations or information, please provide them, and I'll be happy to help you further.