Question

110ab-(11a+5b)² при корне a 11, и еорне b 5​

Answer 1

110ab-(121a²+110ab+25b²)=110ab-121a²-110ab-25b²=-121a²-25b²

Если а=√11 и b=√5, то

-121a²-25b²=-121*11-25*5=-1331-125=-1456

Answer 2

To evaluate the expression 110ab - (11a + 5b)² when a = 11 and b = 5, we can substitute these values into the expression and calculate the result.

Let's substitute a = 11 and b = 5 into the expression:

110(11)(5) - (11(11) + 5(5))²

First, let's simplify the expression inside the parentheses:

110(11)(5) - (121 + 25)²

Next, let's calculate the value inside the parentheses:

110(11)(5) - 146²

Now, let's calculate the exponent:

110(11)(5) - 21316

Next, perform the multiplication:

6050 - 21316

Finally, subtract the two values:

-15266

Therefore, when a = 11 and b = 5, the expression 110ab - (11a + 5b)² evaluates to -15266.