Question

A) 2-5x>x+20 б) x-1/2-3x/2>3x+19/2

Answer 1

Удачи..................

Answer 2

Let's solve the inequalities one by one:

a) 2 - 5x > x + 20

Step 1: Get all x terms on one side of the inequality: Subtract x from both sides: 2 - 5x - x > x + 20 - x 2 - 6x > 20

Step 2: Get the constant term on one side by subtracting 2 from both sides: 2 - 6x - 2 > 20 - 2 -6x > 18

Step 3: Divide both sides by -6, but remember to reverse the inequality since we're dividing by a negative number: x < 18 / -6 x < -3

So the solution for the inequality is x < -3.

b) x - 1/2 - 3x/2 > 3x + 19/2

Step 1: Get all x terms on one side of the inequality: Add 3x/2 and 19/2 to both sides: x - 1/2 - 3x/2 + 3x/2 + 19/2 > 3x + 19/2 + 3x/2 x + 18/2 > (6x + 19)/2

Step 2: Simplify the left side: x + 9 > (6x + 19)/2

Step 3: Get rid of the fraction by multiplying both sides by 2: 2(x + 9) > 6x + 19

Step 4: Distribute the 2 on the left side: 2x + 18 > 6x + 19

Step 5: Get all x terms on one side by subtracting 2x from both sides: 2x + 18 - 2x > 6x + 19 - 2x 18 > 4x + 19

Step 6: Get the constant term on one side by subtracting 19 from both sides: 18 - 19 > 4x + 19 - 19 -1 > 4x

Step 7: Finally, divide both sides by 4, and remember to reverse the inequality since we're dividing by a negative number: x < -1/4

So the solution for the inequality is x < -1/4.