
9 в степени 5х минус 9 в степени 5х-1 равно 8


Ответы на вопрос

9^(5x-1)=y
9^(5x)=9y
9y-y=8
8y=8
y=1
9^(5x-1)=1; 5x-1=0; x=0.2



Ответ: х=0,2
Объяснение: вынесем общий множитель




To solve the equation 9^(5x) - 9^(5x-1) = 8, we need to find the value of x.
Let's first simplify the equation by factoring out a common term: 9^(5x) - 9^(5x-1) = 9^(5x) - (1/9) * 9^(5x) = (9 - 1/9) * 9^(5x) = (8 8/9) * 9^(5x)
Now, the equation becomes: (8 8/9) * 9^(5x) = 8
Next, let's get rid of the fraction by converting 8 8/9 to an improper fraction: 8 8/9 = (8 * 9 + 8) / 9 = 80/9
Now the equation becomes: (80/9) * 9^(5x) = 8
To isolate 9^(5x), divide both sides by (80/9): 9^(5x) = 8 / (80/9)
Now, to simplify the right-hand side, remember that dividing by a fraction is the same as multiplying by its reciprocal: 9^(5x) = 8 * (9/80)
Now, raise both sides to the power of (1/5x) to solve for x: (9^(5x))^(1/5x) = (8 * (9/80))^(1/5x)
On the left side, the exponent (5x) and (1/5x) cancel out, leaving us with just 9. On the right side, we have: 9 = (8 * (9/80))^(1/5x)
Now, raise both sides to the power of (5x) to isolate x: 9^(5x) = (8 * (9/80))^(1/5x)^(5x)
On the left side, the exponent (5x) and (5x) cancel out, leaving us with just 9^1, which is 9. On the right side, we have: 9 = 8 * (9/80)
Now, solve for x: 9 = 8 * (9/80) 9 = 9/10
However, this leads to a contradiction since 9 is not equal to 9/10. It seems there is no solution for the equation, or there might be a mistake in the original equation or its transcription. Please review the equation and ensure it is accurately represented. If you provide the correct equation, I'd be happy to help you solve it.


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