Question

7x-13y=27 , 13x-7y=33​

Answer 1

7х-13у=27/*13

13х-7у=33/*7

=91х-169у=27*13

91х-49у=33*7

91х-91х-169у+49у=27*13-33*7

-120у=-120

у=1

7х-13*1=27

7х=14

х=2

Answer 2

To solve the system of equations:

7x - 13y = 27 ...(1) 13x - 7y = 33 ...(2)

There are multiple ways to solve this system, such as substitution or elimination method. Here, I'll demonstrate the elimination method:

First, let's multiply equation (1) by 13 and equation (2) by 7 to eliminate the variable "y" when adding the equations:

(13) * (7x - 13y) = (13) * (27) (7) * (13x - 7y) = (7) * (33)

Simplifying:

91x - 169y = 351 ...(3) 91x - 49y = 231 ...(4)

Now, we subtract equation (4) from equation (3):

(91x - 169y) - (91x - 49y) = 351 - 231

This simplifies to:

-169y + 49y = 351 - 231 -120y = 120 y = -1

Substituting the value of y = -1 back into equation (1):

7x - 13(-1) = 27 7x + 13 = 27 7x = 27 - 13 7x = 14 x = 14/7 x = 2

Therefore, the solution to the system of equations is x = 2 and y = -1.