Question

R) x2 + 18x - 63 -0.​

Answer 1

х^2 + 18х - 63 = 0

х1 = -21; х2 = 3 (по т. Виета)

Ответ: -21; 3

Answer 2

Ответ: дискриминант 18^2+4*63=576, корни х1=(-18+24)/2=3, х2=(-18-24)/2=-42/2=-21.

Объяснение:

Answer 3

To solve the quadratic equation $x^2 + 18x - 63 = 0$, we can use the quadratic formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In this case, $a = 1$, $b = 18$, and $c = -63$. Substituting these values into the formula, we have:

$x = \frac{-18 \pm \sqrt{18^2 - 4(1)(-63)}}{2(1)}$

Simplifying further:

$x = \frac{-18 \pm \sqrt{324 + 252}}{2}$ $x = \frac{-18 \pm \sqrt{576}}{2}$ $x = \frac{-18 \pm 24}{2}$

Now we have two possibilities:

1. Taking the positive sign:

$x = \frac{-18 + 24}{2} = \frac{6}{2} = 3$

2. Taking the negative sign:

$x = \frac{-18 - 24}{2} = \frac{-42}{2} = -21$

So the solutions to the equation $x^2 + 18x - 63 = 0$ are $x = 3$ and $x = -21$.