Question

Дано : f(x)'=1-sinx f(x)-?

Answer 1

Ответ:

F(x)=x+cosx

Объяснение:

(x)'=1

(cosx)'=-sinx

Answer 2

To find the function f(x) given its derivative f'(x) = 1 - sin(x), we can integrate f'(x) with respect to x.

∫(f'(x)) dx = ∫(1 - sin(x)) dx

Integrating 1 with respect to x gives x, and integrating -sin(x) with respect to x gives cos(x). Therefore:

f(x) = x - cos(x) + C

where C is the constant of integration.