Question

9х во второй - (х+1) =0(7d-13)во второй (9d-25)во второй =0​

Answer 1

Ответ:

Объяснение:

9x²-(x+1)=0

9x²-x-1=0; D=1+36=37

x₁=(1-√37)/18

x₂=(1+√37)/18

Ответ: (1-√37)/18 и (1+√37)/18.

(7d-13)²(9d-25)²=0

(7d-13)²=0; 7d-13=0; 7d=13; d₁=13/7=1 6/7

(9d-25)²=0; 9d-25=0; 9d=25; d₂=25/9=2 7/9

Ответ: 1 6/7 и 2 7/9.

Answer 2

To help you with this equation, let's break it down step by step and solve for the variable "x" and "d".

1. Simplify the equation: 9x^2 - (x + 1) = 0(7d - 13)^2(9d - 25)

2. Expand the square terms: 9x^2 - (x + 1) = 0(49d^2 - 182d + 169)(81d^2 - 450d + 625)

3. Distribute the right-hand side of the equation: 9x^2 - x - 1 = 0

4. Now, we have a quadratic equation in terms of "x". To solve for "x," we can use the quadratic formula:

The quadratic formula is given by: x = (-b ± √(b^2 - 4ac)) / 2a

Where a = 9, b = -1, and c = -1 in our equation.

x = (1 ± √((-1)^2 - 4 * 9 * -1)) / 2 * 9 x = (1 ± √(1 + 36)) / 18 x = (1 ± √37) / 18

So the solutions for "x" are: x = (1 + √37) / 18 x = (1 - √37) / 18

5. For the second part of the equation, it seems there is some confusion with the notation. If you meant to write "d" instead of "0," then we have: (7d - 13)^2(9d - 25) = 0

To solve for "d," we set each factor to zero and solve for "d":

7d - 13 = 0 7d = 13 d = 13 / 7

9d - 25 = 0 9d = 25 d = 25 / 9

So the solutions for "d" are: d = 13 / 7 d = 25 / 9

Please verify if the second part of the equation was intended to be different. If so, provide the correct notation or equation, and I'll be happy to help you further.