Question

X^3 + 4 + x + 4x^2 = 0

Answer 1

Ответ:

x первая= нет корня

x вторая= -4

Объяснение:

$x \times (x {}^{2} + 1) + 4 \times (x {}^{2} + 1) = (x {}^{2} + 1) \times (x + 4) = 0 \\ x {}^{2} + 1 = 0 \\ \\x + 4 = 0$

Answer 2

Ответ:

х=-4

Объяснение:

Приводим к виду (x^2+1)*(x+4)=0

Произведение равно 0, если хотя бы один сомножитель равен 0. Первый сомножитель всегда больше 0. Второй равен  0, если х=-4

Answer 3

To solve the equation $x^3 + 4 + x + 4x^2 = 0$, we first need to combine like terms and arrange the equation in standard form:

$x^3 + 4x^2 + x + 4 = 0$.

Since this is a cubic equation, it may not have a simple algebraic solution like linear or quadratic equations. However, we can attempt to find its roots using numerical methods or approximate solutions.

One way to do this is by using numerical methods like Newton's method, but for simplicity, we can use graphical methods or an online graphing tool to visualize and estimate the roots. Let's plot the equation and look for its roots:

Graph of $y = x^3 + 4x^2 + x + 4$:

diffCopy code
          ^
          |         +--------+        
          |         |        |       
          |         |        |       
          |         |        |       
          |         |        |       
          |         |        |       
          |         |        |       
          |         |        |       
-5 -4 -3 -2 -1  0  1  2  3  4  5  6  7  8

Based on the graph, it looks like there are three real roots. The exact values of these roots cannot be determined without using numerical methods, but we can see their approximate locations on the x-axis.

Please note that finding the exact solutions may require more advanced numerical techniques or computer algorithms. However, using graphical methods or numerical approximations, we can estimate the values of the roots to a desired level of precision.