Question

А) 5(a+2) + (a+2)= б) (x – 3) – 3(x – 3)= в) 7(x – 7) – 3(x – 3)= г)15(8x – 1) – 8(15x+4)= д) 2x(x+1) – 4x(2 – x)= е) 2y(2x – 3y) – 3y(5y – 3x)= ж) 3c(c+d)+3d(c – d)= з) 5b(3a – b) – 3a(5b+a) = и) x(x2+x) – (x2+x+1) = к) 2y2(6y – 1)+3y(y – 4y2) = л) a(2a2 – 3n) – n(2n2+a) = м) b(b3 – b2+b) – (b3 – b2+b) =

Answer 1

Ответ:

$(a + 2) \times 6 \\ - 2(x - 3) \\ 4x - 40 \\ - 17 \\ {x}^{2} - 6x \\ 13xy - 9y \\ 6dc - 3 {d}^{2} - 3 {c}^{2} \\ 5 {b}^{2} - 3 {a}^{2} \\ x ^{3} - x - 1 \\ y ^{2} \\ {b}^{4} - {b}^{3}$

Answer 2

To simplify the given expressions, let's expand and combine like terms:

а) 5(a+2) + (a+2) = 5a + 10 + a + 2 = 6a + 12

б) (x – 3) – 3(x – 3) = x - 3 - 3x + 9 = -2x + 6

в) 7(x – 7) – 3(x – 3) = 7x - 49 - 3x + 9 = 4x - 40

г) 15(8x – 1) – 8(15x+4) = 120x - 15 - 120x - 32 = -47

д) 2x(x+1) – 4x(2 – x) = 2x^2 + 2x - 8x + 4x^2 = 6x^2 - 6x

е) 2y(2x – 3y) – 3y(5y – 3x) = 4xy - 6y^2 - 15y^2 + 9xy = 13xy - 21y^2

ж) 3c(c+d)+3d(c – d) = 3c^2 + 3cd + 3cd - 3d^2 = 3c^2 + 6cd - 3d^2

з) 5b(3a – b) – 3a(5b+a) = 15ab - 5b^2 - 15ab - 3a^2 = -5b^2 - 3a^2

и) x(x^2 + x) – (x^2 + x + 1) = x^3 + x^2 - x^2 - x - 1 = x^3 - x - 1

к) 2y^2(6y – 1) + 3y(y – 4y^2) = 12y^3 - 2y^2 + 3y^2 - 12y^3 = y^2

л) a(2a^2 – 3n) – n(2n^2+a) = 2a^3 - 3an - 2n^3 - an = 2a^3 - an - 2n^3

м) b(b^3 – b^2 + b) – (b^3 – b^2 + b) = b^4 - b^3 + b^2 - b^3 + b^2 - b = b^4 - 2b^3 + 2b^2 - b

These are the simplified expressions for the given equations.