Question

(3-x)(9+3x+x^2)-2x+x^3>7x+7

Answer 1

Смотри вложение.....

Answer 2

Let's simplify and solve the inequality step by step.

Given inequality: (3-x)(9+3x+x^2)-2x+x^3 > 7x + 7

First, let's expand and simplify the left side of the inequality: (3-x)(9+3x+x^2)-2x+x^3 = (27 + 9x + 3x^2) - (9x + 3x^2 + x^3) - 2x + x^3 = 27 + 9x + 3x^2 - 9x - 3x^2 - x^3 - 2x + x^3 = 27 - 2x

Now, we have the inequality: 27 - 2x > 7x + 7

Let's simplify it further: 27 - 2x > 7x + 7

Rearrange the terms: 27 - 7 > 7x + 2x + 7

Combine like terms: 20 > 9x + 7

Subtract 7 from both sides: 20 - 7 > 9x

Simplify: 13 > 9x

Finally, divide both sides by 9 (since the coefficient of x is 9): 13/9 > x

So, the solution to the inequality is x < 13/9.