Question

(y-3)²-(y+5) (y-5)= -2 решить уравнение​

Answer 1

Решение показано на фотографии!)

Answer 2

Ответ:

Объяснение:

(y-3)²-(y+5) (y-5)= -2

у²-6у+9-у²+25= -2

-6у= -2-34

-6у= -36

у= -36÷(-6)

у=6

Answer 3

To solve the quadratic equation $(y-3)^2 - (y+5)(y-5) = -2$, follow these steps:

Step 1: Expand the equation: $(y-3)^2 - (y+5)(y-5) = (y-3)(y-3) - (y^2 - 5y + 5y - 25) = y^2 - 6y + 9 - (y^2 - 25) = y^2 - 6y + 9 - y^2 + 25 = -6y + 34$.

Step 2: Now the equation becomes: $-6y + 34 = -2$.

Step 3: Isolate the variable $y$ on one side by moving constants to the other side: Subtract 34 from both sides: $-6y = -2 - 34$, $-6y = -36$.

Step 4: Solve for $y$: Divide both sides by -6: $y = \frac{-36}{-6}$, $y = 6$.

The solution to the equation is $y = 6$.