Question

X^2+3x√3+5 , если x=√3+1.

Answer 1

Ответ:

Объяснение:

вот и все

Answer 2

To evaluate the expression $x^2 + 3x\sqrt{3} + 5$ when $x = \sqrt{3} + 1$, we can substitute the value of $x$ into the expression and then perform the calculations:

Given $x = \sqrt{3} + 1$, let's substitute this value into the expression:

$$\begin{align*} x^2 + 3x\sqrt{3} + 5 &= (\sqrt{3} + 1)^2 + 3(\sqrt{3} + 1)\sqrt{3} + 5 \\ &= (\sqrt{3})^2 + 2\sqrt{3} \cdot 1 + 1^2 + 3\sqrt{3}(\sqrt{3}) + 3\sqrt{3} \cdot 1 + 5 \\ &= 3 + 2\sqrt{3} + 1 + 3\sqrt{3} + 3\sqrt{3} + 5 \\ &= 10 + 8\sqrt{3}. \end{align*}$$

So, when $x = \sqrt{3} + 1$, the expression $x^2 + 3x\sqrt{3} + 5$ evaluates to $10 + 8\sqrt{3}$.