
(y+4)²=(x-7)²=(5+b)²=(0,3-х) ²=(у+¼)²


Ответы на вопрос

/ - дробь
1) y^2+8y+16
2) x^2-14x+49
3) 25+10b+b^2
4) 0,09-0,6x+x^2
5) y^2+1/2y+1/16



It seems like you have provided a set of equations. Let's break them down and solve for the variables involved.
Equation 1: (y + 4)² = (x - 7)²
This equation represents two squares being equal to each other. To find the solution, we need more information or another equation to relate the variables x and y.
Equation 2: (x - 7)² = (5 + b)²
Again, we have two squares equal to each other. Without further information, we cannot determine the exact values of x and b.
Equation 3: (5 + b)² = (0,3 - x)²
Here, we have two squares equal to each other. However, the notation "(0,3 - x)²" is not clear. Please clarify the expression, or if there was a typographical error, correct it.
Equation 4: (0,3 - x)² = (у + ¼)²
Similar to the previous equation, the notation "(0,3 - x)²" is unclear. Please provide the correct expression or clarify it for me to assist you further.
In summary, based on the equations you provided, it is not possible to find specific solutions for the variables x, y, and b without additional information or clarification for the ambiguous parts of the equations. Please provide more context or any other relevant equations to proceed with solving the system of equations.


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