Question

0,3x(x-4)+1,2x-2,7=2,7

Answer 1

Сначала приведём уравнение к нулю:

$0.3x(x-4)+1.2x-2.7-2.7=0$

Затем раскроем скобки первого члена и сложим числа без переменных; сократим:

$0.3x^{2}-1.2x+1.2x-5.4=0\\0.3x^{2}-5.4=0$

Найдём $x$:

$0.3x^{2}-5.4=0;\\0.3x^{2}=5.4;\\x^{2}=\frac{5.4}{0.3}=\frac{54}{3}=18;\\x=\sqrt{18}.$

Answer 2

To solve the equation 0.3x(x-4) + 1.2x - 2.7 = 2.7, follow these steps:

Step 1: Simplify the equation. 0.3x(x-4) + 1.2x - 2.7 = 2.7 0.3x^2 - 1.2x + 1.2x - 2.7 = 0 0.3x^2 - 2.7 = 0

Step 2: Set the equation equal to zero. 0.3x^2 - 2.7 = 0

Step 3: Divide the equation by 0.3 to simplify. x^2 - 9 = 0

Step 4: Move the constant term to the other side. x^2 = 9

Step 5: Take the square root of both sides. x = ±√9

Step 6: Simplify the square root. x = ±3

So, the solutions to the equation are x = 3 and x = -3.