Question

7x² - 6x-1=0розв'язати рівняння ​

Answer 1

Ответ:

Знаходимо дискримінант:

D=$b^{2}$-4ac=36+28=64         $\sqrt{D}$=8

$x_{1}$=$\frac{-b+\sqrt{D} }{2a}$=$\frac{6+8}{4}$=$\frac{14}{4}$=3,5

$x_{2}$=$\frac{-b-\sqrt{D} }{2a}$=$\frac{6-8}{4}$=$\frac{-2}{4}$=-0,5

Відповідь: 3,5; -0,5

Answer 2

To solve the quadratic equation 7x² - 6x - 1 = 0, we can use the quadratic formula, which states that for an equation of the form ax² + bx + c = 0, the solutions for x are given by:

x = (-b ± √(b² - 4ac)) / 2a

For the given equation, a = 7, b = -6, and c = -1. Substituting these values into the quadratic formula:

x = (6 ± √((-6)² - 4 * 7 * (-1))) / (2 * 7) x = (6 ± √(36 + 28)) / 14 x = (6 ± √64) / 14 x = (6 ± 8) / 14

Now, we have two possible solutions for x:

1. x = (6 + 8) / 14 x = 14 / 14 x = 1

2. x = (6 - 8) / 14 x = -2 / 14 x = -1/7

So, the solutions to the quadratic equation are x = 1 and x = -1/7.