Question

-2x²+7x-6=0 через дискриминант

Answer 1

$- 2 {x}^{2} + 7x - 6 = 0 \\ 2 {x}^{2} - 7x + 6 = 0 \\ d = 49 - 4 \times 2 \times 6 = 49 - 48 = 1 \\ x1 = \frac{7 + \sqrt{1} }{4} \\ x2 = \frac{7 - \sqrt{1} }{4}$

Answer 2

Ответ:

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Answer 3

To find the solutions of the quadratic equation -2x² + 7x - 6 = 0 using the discriminant, we first need to identify the coefficients of the quadratic equation in the standard form ax² + bx + c = 0.

For the given equation, a = -2, b = 7, and c = -6.

The discriminant (Δ) of a quadratic equation is given by Δ = b² - 4ac.

Now, we can calculate the discriminant for our equation:

Δ = (7)² - 4(-2)(-6) = 49 - 48 = 1

Since the discriminant is positive (Δ > 0), the quadratic equation has two distinct real solutions.

The solutions (roots) of the equation can be found using the quadratic formula:

x = (-b ± √Δ) / 2a

Plugging in the values:

x₁ = (-(7) + √1) / 2(-2) = (-7 + 1) / -4 = -6 / -4 = 3/2 = 1.5

x₂ = (-(7) - √1) / 2(-2) = (-7 - 1) / -4 = -8 / -4 = 2

So, the solutions to the quadratic equation -2x² + 7x - 6 = 0 are x = 1.5 and x = 2.