Question

Y(y в квадрате +3)=4y

Answer 1

Ответ:

у(1) = - 1; у(2) = 0; у(3)= 1

Answer 2

To solve the equation Y(y^2 + 3) = 4y, we need to find the value(s) of y that satisfy the equation. Let's go through the steps to solve it:

Step 1: Expand the equation: Y(y^2 + 3) = 4y Yy^2 + 3Y = 4y

Step 2: Move all the terms to one side of the equation to set it to zero: Yy^2 + 3Y - 4y = 0

Step 3: Now we need to solve this quadratic equation for y. The standard form of a quadratic equation is: ax^2 + bx + c = 0, where a, b, and c are constants. In our case: a = Y b = -4 c = 3Y

Step 4: Use the quadratic formula to solve for y: The quadratic formula is given by: y = (-b ± √(b^2 - 4ac)) / 2a

Substitute the values of a, b, and c into the formula: y = (4 ± √((-4)^2 - 4(Y)(3Y))) / 2Y

Simplify further: y = (4 ± √(16 - 12Y^2)) / 2Y y = (4 ± √(4(4 - 3Y^2))) / 2Y y = (4 ± 2√(4 - 3Y^2)) / 2Y y = 2 ± √(4 - 3Y^2) / Y

Now we have two solutions for y:

1. y = (2 + √(4 - 3Y^2)) / Y
2. y = (2 - √(4 - 3Y^2)) / Y

Please note that Y and y are treated as separate variables in this solution. If Y represents a constant value, then you can substitute it with its actual value to find the specific solutions for y. If Y is another variable, then the solution will remain in terms of Y and y.