Question

Сократите дробь 4x^2+x-3/x^2-1

Answer 1

Ответ:

$\frac{4x-3}{x-1}$

Объяснение:

Нужно разложить числитель и знаменатель на скобки.

А потом сократить одинаковые скобки.

$\frac{4x^2+x-3}{x^2-1} =\frac{(x+1)(4x-3)}{(x+1)(x-1)} =\frac{4x-3}{x-1}$

Answer 2

To simplify the given fraction, we first factor both the numerator and the denominator:

Numerator (4x^2 + x - 3): 4x^2 + x - 3 can be factored as (4x - 3)(x + 1).

Denominator (x^2 - 1): x^2 - 1 can be factored as (x + 1)(x - 1).

Now, we can rewrite the original fraction with the factored forms:

(4x^2 + x - 3) / (x^2 - 1) = (4x - 3)(x + 1) / (x + 1)(x - 1).

Now, we can cancel out the common factor (x + 1) from the numerator and the denominator:

(4x - 3)(x + 1) / (x + 1)(x - 1) = (4x - 3) / (x - 1).

So, the simplified fraction is (4x - 3) / (x - 1).