Question

Sin-cos=m найти sin×cos​

Answer 1

Ответ:

Объяснение:

$sinx-cosx=m ,sinx*cosx=?\\(sinx-cosx)^{2} =m^{2} \\sin^{2} x-2*sinx*cosx+cos^{2}x=m^{2} \\sin^{2} x+cos^{2} x-2*sinx*cosx=m^{2} \\1-2*sinx*cosx=m^{2} \\2*sinx*cosx=1-m^{2} |:2\\sinx*cosx=\frac{1-m^{2} }{2}.$

Answer 2

Ответ:

Объяснение:

возведем обе части в квадрат,

sin^2-2sin*cos+cos^2=m^2,  sin^2+cos^2=1,  

-2sin*cos=m^2-1,  sin*cos=(1-m^2)/2

Answer 3

To find the value of sin × cos, we first need to solve the equation sin - cos = m for sin and cos. Then, we can multiply the individual values of sin and cos to find sin × cos.

Let's solve the equation:

sin - cos = m

To solve for sin, add cos to both sides:

sin = m + cos

Next, we need to use the Pythagorean identity to find the value of cos in terms of sin:

sin^2 + cos^2 = 1

cos^2 = 1 - sin^2

cos = √(1 - sin^2)

Now, we can substitute the value of cos in terms of sin back into the equation we found for sin:

sin = m + √(1 - sin^2)

Now, we have a trigonometric equation involving sin only. This equation is not easy to solve algebraically due to the presence of the square root and trigonometric function. However, we can approximate the value of sin × cos by using numerical methods or trigonometric identities, but it will depend on the value of 'm' and the range of solutions you are interested in.

If you have a specific value of 'm' or a range in mind, please provide it, and I can help you approximate sin × cos.