Question

-2 (х – 4) – 4 = 3х (х – 2) – х (3 + х)

Answer 1

Ответ:

-2х+8-4=3х²-6х-3х+3х

-2х+6х+3х-3х-3х²= -8+4

4х-3х²+4=0

a=-3;b=4;c=4

D=b²-4ac

D=(-4)²-4*(-3)*4=16+48=64

-b-D -4-8 -12

x¹=_____ =______=______=2

a*2 -3*2 -6

-b+D -4+8 4 2

x²=_______=_______=_______=-_____

a*2 - 3*2 - 6 3

Answer 2

To solve the given equation, let's first simplify both sides of the equation and then proceed to solve for the variable x step by step:

Equation: -2(x - 4) - 4 = 3x(x - 2) - x(3 + x)

Step 1: Distribute the factors on both sides of the equation. -2x + 8 - 4 = 3x^2 - 6x - 3x - x^2

Simplify each side: -2x + 4 = 2x^2 - 9x

Step 2: Move all terms to one side of the equation to set it equal to zero. 2x^2 - 9x + 2x - 4 = 0

Combine like terms: 2x^2 - 7x - 4 = 0

Step 3: Now we have a quadratic equation in standard form (ax^2 + bx + c = 0). We can solve it using factoring, completing the square, or the quadratic formula. Let's use factoring in this case:

Factor the quadratic expression: (2x + 1)(x - 4) = 0

Now we have two possible solutions: 2x + 1 = 0 or x - 4 = 0

Solve for x in each case: For 2x + 1 = 0: 2x = -1 x = -1/2

For x - 4 = 0: x = 4

So, the solutions to the equation are x = -1/2 and x = 4.