Question

(x+2)² -13=(x-1)(x+9)+3x²

Answer 1

Ответ:

х^2+4x+4-13=x^2+9x-x-9+3x^2

4x+4-13=9x-x-9+3x^2

4x-9=8x-9+3x^2

4x=8x+3x^2

4x-8x-3x^2=0

-4x-3x^2=0

-x(4x+3x)=0

x(4+3x)=0

x=0

4+3x=0

x=-4/3

Answer 2

To solve the given equation, we first need to simplify both sides and then find the values of 'x' that satisfy the equation. Let's go step by step:

Given equation: (x + 2)² - 13 = (x - 1)(x + 9) + 3x²

Step 1: Expand the left-hand side (LHS) of the equation: (x + 2)² - 13 = (x + 2)(x + 2) - 13 = x² + 4x + 4 - 13 = x² + 4x - 9

Step 2: Expand the right-hand side (RHS) of the equation: (x - 1)(x + 9) + 3x² = (x)(x + 9) - 1(x + 9) + 3x² = x² + 9x - x - 9 + 3x² = x² + 9x - x + 3x² - 9 = 4x² + 8x - 9

Now, the equation becomes: x² + 4x - 9 = 4x² + 8x - 9

Step 3: Move all terms to one side to set the equation to zero: x² + 4x - 9 - 4x² - 8x + 9 = 0

Step 4: Combine like terms: -3x² - 4x = 0

Step 5: Factor out 'x' from the equation: x(-3x - 4) = 0

Step 6: Set each factor to zero and solve for 'x':

1. x = 0
2. -3x - 4 = 0 -3x = 4 x = -4/3

So, the solutions to the equation are x = 0 and x = -4/3.