Question

Раскрыть скобки 7(x-5)(x+3)

Answer 1

Ответ:

Объяснение:

сначала перемножим скобки:

7(x-5)(x+3) = 7 (x²+3x-5x-15)=7 (x²-2x-15)

теперь умножим каждое слагаемое на 7:

7x²-14x-105

Answer 2

Объяснение:

7(x-5)(x+3)

(7x-35)×(x+3)

7x^2+21x-35x-105

7x^2-14x-105

Answer 3

To expand the expression 7(x-5)(x+3), you can use the distributive property, also known as the FOIL method (First, Outer, Inner, Last). Here's the step-by-step expansion:

1. Multiply the first terms in each pair of parentheses: 7 * x = 7x

2. Multiply the outer terms in each pair of parentheses: 7 * 3 = 21

3. Multiply the inner terms in each pair of parentheses: -5 * x = -5x

4. Multiply the last terms in each pair of parentheses: -5 * 3 = -15

Now, combine all the terms to get the final expression:

7x + 21 - 5x - 15

Finally, combine like terms:

(7x - 5x) + (21 - 15)

2x + 6

So, the expanded form of 7(x-5)(x+3) is 2x + 6.