Question

2√×+6×-8=0 Решить уравнение

Answer 1

Ответ:

×=1

Объяснение:

Я думаю это правильно

Answer 2

Ответ:х=-2,6

Объяснение:

Answer 3

To solve the quadratic equation 2x^2 + 6x - 8 = 0, we can use the quadratic formula, which is given by:

x = (-b ± √(b^2 - 4ac)) / 2a

where a, b, and c are the coefficients of the quadratic equation in the standard form ax^2 + bx + c = 0.

For the given equation, a = 2, b = 6, and c = -8.

Now, let's plug these values into the quadratic formula and solve for x:

x = (-(6) ± √(6^2 - 4 * 2 * -8)) / 2 * 2 x = (-6 ± √(36 + 64)) / 4 x = (-6 ± √100) / 4 x = (-6 ± 10) / 4

Now, we get two possible solutions:

1. x = (-6 + 10) / 4 x = 4 / 4 x = 1

2. x = (-6 - 10) / 4 x = -16 / 4 x = -4

So, the solutions to the equation 2x^2 + 6x - 8 = 0 are x = 1 and x = -4.