Question

36.20 a) 4(a + 1) + 3a > 7a + 2; решите неравенство ​

Answer 1

....................................

Answer 2

Let's solve the inequality step by step:

4(a + 1) + 3a > 7a + 2

First, we simplify the expression on both sides of the inequality:

4a + 4 + 3a > 7a + 2

Next, we combine like terms:

7a + 4 > 7a + 2

Since we have 7a on both sides of the inequality, we can subtract 7a from both sides to eliminate it:

7a - 7a + 4 > 7a - 7a + 2

This simplifies to:

4 > 2

Since 4 is greater than 2, the inequality 4(a + 1) + 3a > 7a + 2 is true for all values of 'a'. In other words, there is no restriction on 'a' that satisfies this inequality. Therefore, the solution to the inequality is the set of all real numbers.