Question

3(4x-2y+1)-2(5x-y+4)=23,2(x+6y-9)+5(2x-4y+7)=105

Answer 1

Ответ:

1)12х-6у+3-10х+2у-8=23,2х+139,2у-208,8+10х-20у+35=105

2)2х-4у-5=33,2х+119,2у-173,8=105

3)(2х-4у-5)-(33,2х+119,2у-173,8)=0

4)2х-4у-5-33,2х-119,2у+173,8=0

5)-31,2х-123,2у+168,8=0

6)-31,2х-123,2у=-168,8

Объяснение:

1)сначало раскрываем скобки

2)находим подобные слагаемые и считаем

3)дальше вычитаем из одного выражение другое, но так как они равно, то разность их будет равна 0

я не совсем понял что тебе надо найти, сорян если неправильно

Answer 2

To solve the given system of equations:

1. 3(4x - 2y + 1) - 2(5x - y + 4) = 23
2. 2(x + 6y - 9) + 5(2x - 4y + 7) = 105

Let's simplify and solve each equation step by step:

1. Simplify the first equation:

12x - 6y + 3 - 10x + 2y - 8 = 23 (12x - 10x) + (-6y + 2y) + (3 - 8) = 23 2x - 4y - 5 = 23 2x - 4y = 28 [Equation 1]

2. Simplify the second equation:

2x + 12y - 18 + 10x - 20y + 35 = 105 (2x + 10x) + (12y - 20y) + (-18 + 35) = 105 12x - 8y + 17 = 105 12x - 8y = 88 [Equation 2]

Now we have a system of linear equations:

1. 2x - 4y = 28
2. 12x - 8y = 88

To solve this system, we can use the method of substitution or elimination. Let's use the elimination method:

Multiply Equation 1 by 6 and Equation 2 by 1 to make the coefficients of x in both equations equal:

12(2x - 4y) = 6(28) 72x - 48y = 168 [Equation 3]

12(12x - 8y) = 12(88) 144x - 96y = 1056 [Equation 4]

Now we'll subtract Equation 3 from Equation 4 to eliminate x:

(144x - 96y) - (72x - 48y) = 1056 - 168 144x - 96y - 72x + 48y = 888 72x - 48y = 888 [Equation 5]

Now we have two equations:

1. 72x - 48y = 888 [Equation 5]
2. 12x - 8y = 88 [Equation 2]

Let's solve this new system of equations:

Multiply Equation 2 by 6 to make the coefficients of x in both equations equal:

6(12x - 8y) = 6(88) 72x - 48y = 528 [Equation 6]

Now we can subtract Equation 5 from Equation 6 to eliminate x:

(72x - 48y) - (72x - 48y) = 528 - 888 0 = -360

The equation 0 = -360 is not true. This means that the system of equations is inconsistent, and there is no solution that satisfies both equations simultaneously.

Therefore, the given system of equations has no solution.