Question

(а^5 - 2 ) (а^5 + 2) = (5х-7) (5х+7)=

Answer 1

Ответ:

(a^5)^2-2^2=a^10-4

(5x)^2-7^^2=25x^2-49

Answer 2

It looks like you've provided two different equations with variables "a" and "x". Let's solve each equation separately:

Equation 1: (а^5 - 2 ) (а^5 + 2)

This equation is a difference of squares, which can be factored as follows: (а^5 - 2 ) (а^5 + 2) = (а^5)^2 - (2)^2 = а^(10) - 4

Equation 2: (5х-7) (5х+7)

This equation is also a difference of squares, which can be factored as follows: (5х - 7) (5х + 7) = (5х)^2 - (7)^2 = 25х^2 - 49

So, the factored expressions are:

1. (а^5 - 2 ) (а^5 + 2) = а^(10) - 4
2. (5х - 7) (5х + 7) = 25х^2 - 49

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