Question

3х + 4у =12; 2х - 3у =-26

Answer 1

Ответ:

$3x + 4y = 12 \\ 3x + 4y - 12 = 12 - 12 \\ 3x + 4y - 12 = 0$

$2x - 3y = - 26 \\ 2x - 3y + 26 = - 26 + 26 \\ 2x - 3y + 26 = 0$

Answer 2

Ответ:

3x+4у=12    2х-3у=-26

3х=12           2х=-26

х=4               х=-13

12+4у=12      -26-3у=26

4у=0              -3у=-52

у=0                 у=17 1/3

(4;0)                (-13;17 1/3)

Объяснение:

Answer 3

It looks like you have a system of linear equations with two variables, x and y. The system is as follows:

1. $3x + 4y = 12$
2. $2x - 3y = -26$

To solve this system of equations, we can use various methods such as substitution, elimination, or matrix methods. Here, I'll use the elimination method:

Step 1: Multiply both sides of the second equation by 2 to make the coefficients of x in both equations equal:

$2(2x - 3y) = 2(-26)$ $4x - 6y = -52$

Now the system becomes:

1. $3x + 4y = 12$
2. $4x - 6y = -52$

Step 2: Add the modified second equation to the first equation to eliminate y:

$(3x + 4y) + (4x - 6y) = 12 + (-52)$ $7x - 2y = -40$

Step 3: Solve the new equation for y:

$-2y = -40 - 7x$ $y = \frac{7x - 40}{2}$

Step 4: Substitute the value of y into the first equation:

$3x + 4\left(\frac{7x - 40}{2}\right) = 12$

Now solve for x:

$3x + 14x - 80 = 24$ $17x = 104$ $x = \frac{104}{17}$

Step 5: Substitute the value of x back into the expression for y:

$y = \frac{7\left(\frac{104}{17}\right) - 40}{2}$ $y = \frac{728}{17} - \frac{40}{2}$ $y = \frac{728 - 340}{17}$ $y = \frac{388}{17}$

So, the solution to the system of equations is approximately:

$x \approx 6.12$ $y \approx 22.82$

Keep in mind that these are approximate decimal values. If you need more accurate fractions, you can leave the answers in fractional form.