Question

2a+2ab+3b-a-2b= 7a+2b-(6a+b)= 3\2a-b+3\4a-7\5b= 7\1ab×23m-7\2abm=

Answer 1

Ответ:

Смотри в решении

Объяснение:

1) $2a+2ab+3b-a-2b=a+2ab+b=a(1+2b)+b$

2) 7a + 2b - (6a + b) = 7a + 2b - 6a - b = a + b

3) $\frac{3}{2a-b} +\frac{3}{4a}-\frac{7}{5b}\\\\\frac{3ab+3*5b(2a-b)-7*4a(2a-b)}{20ab(2a-b)}\\ \frac{46ab-15b^2-56a^2}{20ab(2a-b)}$

4)$\frac{7}{ab}*\frac{23m-7}{2abm} \\\frac{7(23m-7)}{a^2b^2m}$

Answer 2

Let's simplify each of the equations:

1. 2a + 2ab + 3b - a - 2b = 7a + 2b - (6a + b) Simplifying the left side: 2a + 2ab + 3b - a - 2b = a + 2ab + b Simplifying the right side: 7a + 2b - (6a + b) = 7a + 2b - 6a - b = a + b Therefore, the equation simplifies to: a + 2ab + b = a + b

2. 3/2a - b + 3/4a - 7/5b = 7/1ab × 23m - 7/2abm Simplifying the left side: (3/2a + 3/4a) - (b + 7/5b) = (6/4a + 3/4a) - (5/5b + 7/5b) = 9/4a - 12/5b Simplifying the right side: (7/1ab) × (23m) - (7/2abm) = (161m/ab) - (49m/2ab) Therefore, the equation simplifies to: 9/4a - 12/5b = 161m/ab - 49m/2ab

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