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ПОМОГИТЕ !!!))) Реши систему уравнений: {x+y=−4 x−y=19 ( ; ). Смотреть ответ lanamilova8 lanamilova8 {х+у=4 {х=19+у (в одной скобочке) 19+у+у=-4 у=-23/2 х=19-23/2 х=15/2 (х; у)=(15,2; -23/2) {15/2-23/2=-4. -> {-4=-4 {15/2-(-23/2)=19. ->{19=19 Решение: (х; у)=(15,2; -23/2) Новые вопросы в Алгебра (x+2)²+(x-3y)²=0 срочно даю дофига ​ Помогите пожалуйста X^2-10x+16>=0 6. Відомо, що а+b=5, ab=-2. Знайдіть значення виразу (a-b)в квадраті​ Знайти f(27), якщо f(x) = √3х​a) 9 b)-9 в) 4 г)6 Знайдіть знаменник геометричної прогресії... 75; 15; 3;.....​ Предыдущий Следующий Вместе мы знаем больше Этот сайт использует cookies Политика Cookies . Вы можете указать условия хранения и доступ к cookies в своем браузере. 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Answer 1

Конечно, я помогу вам разобраться с этими математическими вопросами.

1. Система уравнений: $\begin{cases} x + y = -4 \\ x - y = 19 \end{cases}$

   Решение: Сложим оба уравнения, чтобы избавиться от $y$: $(x + y) + (x - y) = -4 + 19$ $2x = 15$ $x = \frac{15}{2} = 7.5$

   Подставим значение $x$ в первое уравнение: $7.5 + y = -4$ $y = -4 - 7.5$ $y = -11.5$

   Таким образом, решение системы уравнений: $x = 7.5$, $y = -11.5$.

2. Неравенство $x^2 - 10x + 16 \geq 0$: Давайте найдем корни квадратного уравнения $x^2 - 10x + 16 = 0$: $x^2 - 10x + 16 = (x - 8)(x - 2) = 0$

   Корни: $x = 8$ и $x = 2$.

   Теперь мы знаем, что квадратное выражение равно нулю при $x = 8$ или $x = 2$. Отсюда видно, что оно будет положительным или равным нулю в интервалах $(-\infty, 2]$ и $[8, +\infty)$, и отрицательным в интервале $(2, 8)$.

3. Выражение $(a - b)^2$, где $a + b = 5$ и $ab = -2$: Раскроем квадрат: $(a - b)^2 = a^2 - 2ab + b^2$

   Заменим $ab$ по условию: $(a - b)^2 = a^2 - 2(-2) + b^2 = a^2 + 4 + b^2$

4. Вычисление $f(27)$, где $f(x) = \sqrt{3x}$: Просто подставим $x = 27$ в выражение $f(x)$: $f(27) = \sqrt{3 \cdot 27} = \sqrt{81} = 9$

   Ответ: $f(27) = 9$.

5. Знаменник геометрической прогрессии: Здесь даны первый член $a_1 = 75$ и общий знаменатель $q = \frac{15}{75} = \frac{1}{5}$. Знаменники геометрической прогрессии могут быть вычислены по формуле: $a_n = a_1 \cdot q^{(n-1)}$

   Где $n$ - номер члена прогрессии.

   Для первого члена ($n = 1$): $a_1 = 75$

   Для второго члена ($n = 2$): $a_2 = 75 \cdot \left(\frac{1}{5}\right)^1 = 15$

   Для третьего члена ($n = 3$): $a_3 = 75 \cdot \left(\frac{1}{5}\right)^2 = 3$

   Таким образом, знаменники геометрической прогрессии: 75, 15, 3.

Если у вас остались дополнительные вопросы, не стесняйтесь спрашивать!