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Розв'яжіть рівняння методом додавання {2х-5у=-7 {5х-у=9 пожалуйста очень срочно​ Смотреть ответ dnepr1 dnepr1 Надо привести заданные уравнение к такому виду, чтобы одна из переменных в обоих уравнениях имела одинаковые коэффициенты, но с разным знаком. {2х-5у=-7                          2х - 5у = -7 {5х-у=9 умн. на (-5) =     -25х + 5у = -45                                            -23х         = -52, х = -52/(-23) = 52/23, у = 5х - 9 = 5*(52/23) - 9 = 53/23. Проверяем: 2*(52/23) - 5*(53/23) = (104 - 265)/23 = -7. Решение верное. Ответ: х = (52/23), у = (53/23). Новые вопросы в Алгебра Велосипедист выехал с постоянной скоростью из города А в город В, расстояние между которыми равно 224 км. Отдохнув он отправился обратно в А, увеличив … скорость на 2 км\ч. По пути он сделал остановку на 2 часа, в результате чего затратил на обратный путь столько же времени сколько на путь из А в В. Найдите скорость велосипедиста на пути из B в А? Велосипедист выехал с постоянной скоростью из города А в город В, расстояние между которыми равно 112 км. Отдохнув, он отправился обратно в А, увеличи … в скорость на 9 км/ч. По пути он сделал остановку на 4 часа, в результате чего затратил на обратный путь столько же времени, сколько на путь из А в В. Найдите скорость велосипедиста на пути из B а А нужно соединить цифра по картинкам, хелп​ пожалуст) не могу решить задачу для зачета по математике( допоможіть будь ласка! Предыдущий Следующий Вместе мы знаем больше Этот сайт использует cookies Политика Cookies . Вы можете указать условия хранения и доступ к cookies в своем браузере. 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Answer 1

Для решения этой задачи, давайте обозначим неизвестные величины:

1. Скорость велосипедиста на пути из города А в город В - пусть это будет V км/ч.
2. Время, затраченное на путь из города А в город В - пусть это будет t часов.

Тогда расстояние между городами А и В можно выразить как:

Расстояние = Скорость x Время 224 км = V x t

Теперь, когда он возвращается из города В в город А с увеличенной скоростью (V + 2) км/ч, и делает остановку на 2 часа, он также затрачивает то же количество времени, сколько и в путь в город В. Обозначим это время как t_обратный.

Тогда:

224 км = (V + 2) x t_обратный

Так как он затратил на обратный путь столько же времени, сколько на путь в город В, мы можем записать:

t_обратный = t

Теперь у нас есть два уравнения:

1. 224 = Vt
2. 224 = (V + 2)t_обратный

Из уравнения 2, заменяя t_обратный на t, мы получаем:

224 = (V + 2)t

Теперь у нас есть два уравнения с двумя неизвестными (V и t). Мы можем решить их систему. Давайте разделим уравнение 1 на уравнение 2:

(Vt) / ((V + 2)t) = 1

t и t сокращаются:

V / (V + 2) = 1

Теперь, чтобы избавиться от дроби, можно умножить обе стороны на (V + 2):

V = V + 2

Теперь выразим V:

V - V = 2

0 = 2

Это противоречие! Это означает, что задача имеет некорректные начальные условия. Нет такой скорости V, при которой велосипедист мог бы затратить на обратный путь столько же времени, сколько на путь в город В, увеличив скорость на 2 км/ч и делая остановку на 2 часа.