Question

(x-1)2 -4(x-1) + 4 = 0​

Answer 1

Ответ:

6

Решение:

На фотографии:

Answer 2

To solve the quadratic equation $(x-1)^2 - 4(x-1) + 4 = 0$, we can follow these steps:

Step 1: Distribute the terms: Expand the terms within the equation to simplify it:

$(x-1)^2 - 4(x-1) + 4 = 0$ $x^2 - 2x + 1 - 4x + 4 + 4 = 0$ $x^2 - 6x + 9 = 0$

Step 2: Solve the quadratic equation: Now we have a quadratic equation in the form $ax^2 + bx + c = 0$, where $a = 1$, $b = -6$, and $c = 9$. To solve this equation, we can use the quadratic formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Plugging in the values:

$x = \frac{-(-6) \pm \sqrt{(-6)^2 - 4(1)(9)}}{2(1)}$ $x = \frac{6 \pm \sqrt{36 - 36}}{2}$ $x = \frac{6 \pm 0}{2}$ $x = 3$

Since the square root term resulted in 0, there's only one solution:

$x = 3$

So, the solution to the quadratic equation $(x-1)^2 - 4(x-1) + 4 = 0$ is $x = 3$.