Question

A = 4 j-2 i +k​

Answer 1

Ответ:

$\vec{a}=4\vec{j}-2\vec{i}+\vec{k}\ \ \to \ \ \ \vec{a}=-2\vec{i}+4\vec{j}+\vec{k}\\\\\vec{a}=(-2\, ;\, 4\, ;\, 1\, )$

Answer 2

The vector A can be represented as A = 4j - 2i + k, where i, j, and k are the standard unit vectors in the x, y, and z directions respectively.

In terms of components, A can be written as A = (-2)i + (4)j + (1)k.

So, the vector A has a component of -2 along the x-axis (i-direction), 4 along the y-axis (j-direction), and 1 along the z-axis (k-direction).