Question

(x-1)(x²+6x+9)x=(x+3)x2(x-5)

Answer 1

Ответ:

X= 0, (-3) и 3/7

Answer 2

Ответ: x1=0, x2=-3

Объяснение:

x(x-1)(x+3)^2=(x+3)2x(x-5)

x(x-1)(x+3)^2-(x+3)2x(x-5)=0

x(x+3)((x-1)(x+3)-2x+10)=0

x(x+3)(x^2+2x-2x+10-3)=0

x(x+3)(x^2+7)=0, след

x=0 или x=-3

Answer 3

To solve the given equation $(x-1)(x²+6x+9)x=(x+3)x^2(x-5)$, we'll start by simplifying both sides of the equation and then solving for $x$.

Let's break down the steps:

1. Expand both sides of the equation: Left side: (x-1)(x²+6x+9)x = x(x²+6x+9) - 1(x²+6x+9)x = x³ + 6x² + 9x - x³ - 6x² - 9x = 0 Right side: \((x+3)x^2(x-5) = x^2(x+3)(x-5) = x^3(x-5+3) = x^3(x-2)

2. Simplify both sides: Equation becomes: $0 = x^3(x-2) - x^3(x-2) = 0$

3. Since both sides are identical and equal to 0, the equation holds true for all values of $x$.

Therefore, the solution to the given equation is all real numbers $x$, meaning any real value of $x$ you plug into the equation will satisfy it.