Question

(-3)^17 *(3^2)^7:3^29

Answer 1

Ответ:

-9

Объяснение:

$\frac{(-3)^{17} *(3^{2}) ^7}{3^{29}}=\frac{-3^{17}*3^{14}}{3^{29}}=-\frac{3^{31}}{3^{29}}=-3^2=-9$

Answer 2

Let's break down the expression step by step:

1. (-3)^17: This means raising -3 to the power of 17. The result will be a negative value because an odd power of a negative number is negative.

2. (3^2)^7: This means raising 3^2 (which is 9) to the power of 7. So, (9)^7 = 9^7.

3. 3^29: This is simply 3 raised to the power of 29.

Now, let's put it all together:

(-3)^17 * (3^2)^7 / 3^29 = -3^17 * 9^7 / 3^29

Since 3^2 equals 9, we can simplify further:

= -3^17 * 9^7 / 3^29 = -3^17 * 3^(2*7) / 3^29 = -3^(17 + 14) / 3^29 = -3^31 / 3^29

When you divide two numbers with the same base and different exponents, you can subtract the exponents:

= -3^(31 - 29) = -3^2 = -9

So, the result of the expression (-3)^17 * (3^2)^7 / 3^29 is -9.