Question

1)(2y+7)(7-2y) =49 пжжжжжжжжжжжж помогите решить 2)(x²+3)²-7(x²+3)+12=0

Answer 1

Ответ:

1) уравнение тождественно равное

2) х = 0

Answer 2

Ответ:

ответ во вложении....

Answer 3

1. Let's solve the equation step by step:

(2y + 7)(7 - 2y) = 49

Expand the left side:

14y - 4y^2 + 49 - 14y = 49

Combine like terms:

-4y^2 + 49 = 49

Subtract 49 from both sides:

-4y^2 = 0

Divide both sides by -4:

y^2 = 0

Take the square root of both sides:

y = 0

So the solution to the equation is y = 0.

2. Let's solve the equation step by step:

(x^2 + 3)^2 - 7(x^2 + 3) + 12 = 0

Let's simplify the equation by substituting a variable:

Let a = x^2 + 3

Substituting a into the equation, we have:

a^2 - 7a + 12 = 0

Factor the quadratic equation:

(a - 3)(a - 4) = 0

Set each factor equal to zero:

a - 3 = 0 or a - 4 = 0

Solve for a:

a = 3 or a = 4

Substitute back the value of a:

For a = 3: x^2 + 3 = 3 x^2 = 0 x = 0

For a = 4: x^2 + 3 = 4 x^2 = 1 x = ±√1 x = ±1

So the solutions to the equation are x = 0, x = 1, and x = -1.