Question

(x +y)²- (x-3)²=0......

Answer 1

Объяснение:

x²+2xy+y²-x²+6x-9=0

2xy+6x+y²-9=0

2x(y+3)+y²-9=0

2x(y+3)+(y-3)(y+3)=0

(2x+y+3)(y-3)=0

Answer 2

The given equation is:

(x + y)² - (x - 3)² = 0

Let's simplify this equation step by step:

1. Expand the squares: (x + y)² = x² + 2xy + y² (x - 3)² = x² - 6x + 9

2. Substitute the expanded values back into the equation: x² + 2xy + y² - (x² - 6x + 9) = 0

3. Distribute the negative sign within the parentheses: x² + 2xy + y² - x² + 6x - 9 = 0

4. Combine like terms: 2xy + 6x + y² - 9 = 0

So, the simplified equation is: 2xy + 6x + y² - 9 = 0