Question

(x+3)(x-10)<(x-5)(x-2)??? ​

Answer 1

Ответ:

Объяснение:

3×+10× больше за 5×+2×

Answer 2

To solve this inequality, let's first expand both sides of the inequality and then simplify:

Left side: $(x+3)(x-10) = x^2 - 10x + 3x - 30 = x^2 - 7x - 30.$

Right side: $(x-5)(x-2) = x^2 - 2x - 5x + 10 = x^2 - 7x + 10.$

Now the inequality becomes: $x^2 - 7x - 30 < x^2 - 7x + 10.$

Subtracting $x^2 - 7x$ from both sides: $-30 < 10.$

This statement is always true, regardless of the value of $x$. Therefore, the solution to the inequality is all real numbers $x$. In interval notation, this can be expressed as $(-\infty, \infty)$.