Question

1) 2x(3x-4)-3x(2x+5)=7 2) x²+4x+1=x(x+2) 3) 3x(x+1)-2x(5x+3)=7x(2-x)+34 4) 8(x²-1)-3x(x+2)=5x²-6x-5

Answer 1

Ответ:

4

Объяснение:

1)x=-7/23

2)x=-1/2

3)x=-2

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Answer 2

Sure, I can help you solve these equations step by step. Let's go through each of them:

1. $2x(3x-4) - 3x(2x+5) = 7$

First, distribute the terms within the parentheses:

$6x^2 - 8x - 6x^2 - 15x = 7$

Combine like terms:

$-23x = 7$

Divide both sides by -23:

$x = -\frac{7}{23}$

2. $x^2 + 4x + 1 = x(x+2)$

Distribute $x$ on the right side:

$x^2 + 4x + 1 = x^2 + 2x$

Subtract $x^2 + 2x$ from both sides:

$1 = 0$

This equation doesn't hold true for any value of $x$, so there is no solution.

3. $3x(x+1) - 2x(5x+3) = 7x(2-x) + 34$

First, distribute the terms within the parentheses:

$3x^2 + 3x - 10x^2 - 6x = 14x - 7x^2 + 34$

Combine like terms:

$-7x^2 - 3x = 14x - 7x^2 + 34$

Subtract $14x$ from both sides:

$-24x = 34$

Divide both sides by -24:

$x = -\frac{17}{12}$

4. $8(x^2 - 1) - 3x(x+2) = 5x^2 - 6x - 5$

First, distribute the terms within the parentheses:

$8x^2 - 8 - 3x^2 - 6x = 5x^2 - 6x - 5$

Combine like terms:

$5x^2 - 6x - 8 = 5x^2 - 6x - 5$

Subtract $5x^2 - 6x$ from both sides:

$-8 = -5$

This equation doesn't hold true for any value of $x$, so there is no solution.

Please double-check your equations and calculations if you encounter any discrepancies.