Question

A) 3√5+7√3-10√3= б)7√11+2√22

Answer 1

Ответ:

Объяснение:

A) 3√5+7√3-10√3=3√5- 3√3=3 (√5- √3)

б)7√11+2√22= 7√11+2√2*11= 7√11+2√2*√11= √11 (7+2√2)= √11 (7+√8)

Answer 2

It seems like you're comparing two algebraic expressions. Let's simplify each expression step by step:

A) $3\sqrt{5} + 7\sqrt{3} - 10\sqrt{3}$ First, combine the terms with the same radical: $3\sqrt{5} + (7 - 10)\sqrt{3} = 3\sqrt{5} - 3\sqrt{3}$

B) $7\sqrt{11} + 2\sqrt{22}$ You can simplify $\sqrt{22}$ by breaking it down into its prime factors: $\sqrt{22} = \sqrt{2 \cdot 11} = \sqrt{2} \cdot \sqrt{11}$

Now substitute this back into expression B: $7\sqrt{11} + 2\sqrt{2} \cdot \sqrt{11} = (7 + 2\sqrt{2})\sqrt{11}$

So, the simplified expressions are: A) $3\sqrt{5} - 3\sqrt{3}$ B) $(7 + 2\sqrt{2})\sqrt{11}$

If you're looking to compare these two expressions for equality or some other purpose, you can use these simplified forms.