
1) y=x3³, 2) y=5x³, 3) y= ¼x³ 4) y=4x³


Ответы на вопрос

Ответ:
1) 0=х*27
0=27х
27х=0
х=0
2)0=5х^3
5х^3=0
х^3=0
х=0
3)0=1/4х^3
1/4х^3=0
х^3=0
х=0
4)0=4х^3
4х^3=0
х^3=0
х=0



It seems like you have provided four different equations, each representing a function of the form y = f(x) where f(x) is a cubic function of x. Here are the equations you've provided:
- y = x^3
- y = 5x^3
- y = (1/4)x^3
- y = 4x^3
These equations represent cubic functions, and each one behaves differently based on the value of the coefficient in front of x^3. Here's a brief description of each function:
y = x^3: This is a basic cubic function where the coefficient of x^3 is 1. It has one real root at x = 0 and behaves similarly to a typical cubic function.
y = 5x^3: This cubic function has a coefficient of 5 in front of x^3. It is vertically stretched by a factor of 5 compared to the basic cubic function. It still has one real root at x = 0 but grows much faster as x moves away from zero.
y = (1/4)x^3: This cubic function has a coefficient of (1/4) in front of x^3. It is vertically compressed compared to the basic cubic function. It still has one real root at x = 0 but grows more slowly as x moves away from zero.
y = 4x^3: This cubic function has a coefficient of 4 in front of x^3. It is vertically stretched by a factor of 4 compared to the basic cubic function. It still has one real root at x = 0 but grows faster as x moves away from zero, similar to the second equation.
Each of these functions represents a different cubic curve with varying steepness and behavior.


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