Question

(0,05y-2,3x)(y-0,2x)​

Answer 1

Ответ:

$0.05y^{2} - 2.3xy + 0.46x^{2}$

Объяснение:

$(0.05y - 2.3x)(y - 0.2x) \\ 0.05y \times y - 0.05y \times 0.2x - 2.3xy - 2.3x \times ( - 0.2x) \\ 0.05y^{2} - 0.01xy - 2.3xy + 0.46x^{2} \\ 0.05y^{2} - 2.31xy + 0.46x^{2}$

Answer 2

To multiply the two expressions (0.05y - 2.3x) and (y - 0.2x), you can use the distributive property, also known as FOIL (First, Outer, Inner, Last).

Here's how you can do it step by step:

(0.05y - 2.3x)(y - 0.2x)

First, multiply the first terms in each expression: 0.05y * y = 0.05y^2

Next, multiply the outer terms: 0.05y * (-0.2x) = -0.01xy

Then, multiply the inner terms: (-2.3x) * y = -2.3xy

Finally, multiply the last terms: (-2.3x) * (-0.2x) = 0.46x^2

Now, add all these results together:

0.05y^2 - 0.01xy - 2.3xy + 0.46x^2

Now, simplify by combining like terms:

0.05y^2 - 2.31xy + 0.46x^2

So, the product of (0.05y - 2.3x) and (y - 0.2x) is 0.05y^2 - 2.31xy + 0.46x^2.