Question

2 cos 2П/3 - 3sin^2 3П/4 - 5tg П

Answer 1

2 cos 2П/3 - 3sin^2 3П/4 - 5tg П = 2cos(П - П/3) - 3sin^2 (П - П/4) - 5tgП =

- 2 cos П/3 - 3sin^2 П/4 - 5tgП = -2*1/2 - 3*$(\frac{\sqrt{2} }{2} )^{2}$ - 5*0 = -1 - 3/2  = $-\frac{5}{2}$

Answer 2

Ответ:

-2.5

Объяснение:

cos 2P/3=-1/2

sin^2 3P/4 = 1/2

tg P = 0

-1-1.5-0=-2.5

Answer 3

To solve this expression, let's break it down step by step:

1. Start with the first term: 2 cos (2π/3). The cosine function of 2π/3 is -1/2. So, substituting the value, we have: 2 * (-1/2) = -1.

2. Move on to the second term: 3 sin^2 (3π/4). The sine function of 3π/4 is (√2)/2. Squaring it, we get ((√2)/2)^2 = 2/4 = 1/2. So, the term becomes: 3 * (1/2) = 3/2.

3. Finally, we have the last term: 5 tan(π). The tangent function of π is equal to 0 since it represents the tangent of a 180-degree angle, which is 0. Therefore, the term becomes: 5 * 0 = 0.

Putting it all together, the expression simplifies to: -1 + 3/2 + 0 = -1/2.

So, 2 cos (2π/3) - 3 sin^2 (3π/4) - 5 tan(π) equals -1/2.